
Probability – Conditional Probability & Multiplication Rule
Maths · Grade 11 · Week 40 · 25 questions
All 25 questions in this Probability – Conditional Probability & Multiplication Rule quiz
Grade 11 Maths — Probability – Conditional Probability & Multiplication Rule: 25 practice questions with instant scoring and explanations.
- Conditional probability P(A|B) is defined as:
- The multiplication rule states: P(A ∩ B) =:
- For independent events A and B, P(A|B) =:
- Bayes' Theorem states:
- If A and B are independent events, then P(A|B) =:
- The law of total probability states: P(A) =:
- If P(A) = 0.3, P(B) = 0.5, and A and B are independent, then P(A ∩ B) =:
- If P(A|B) = 0.6 and P(B) = 0.4, then P(A ∩ B) =:
- For two events A and B, if they are mutually exclusive, then P(A|B) =:
- Conditional probability P(A|B) is NOT defined when:
- If P(B|A) = 0.8, P(A) = 0.5, then P(A ∩ B) =:
- The multiplication rule for three events: P(A ∩ B ∩ C) =:
- If P(A) = 0.6 and P(B|A) = 0.5, what is P(A ∩ B)?
- For independent events, the multiplication rule simplifies to:
- P(B|A) can be calculated using:
- If events are independent, then P(B|A) =:
- In Bayes' theorem, P(A|B) depends on:
- If A and B are exhaustive and mutually exclusive, then P(A ∪ B) =:
- For mutually exclusive events A and B, P(A|B) =:
- If P(A|B) = 0.7 and P(B) = 0.3, then P(A ∩ B) =:
- The complement of conditional probability: P(A'|B) =:
- If P(B|A) = 0.5 and P(A) = 0.8, is P(A ∩ B) = 0.4?
- Given P(A) = 0.4, P(B) = 0.3, and P(A ∩ B) = 0.1, then P(A|B) =:
- Bayes' theorem is particularly useful for:
- If P(A) = 0.5, P(B) = 0.6, and A and B are independent, P(A ∪ B) = :
Question 1 of 250 correct so far