
Equations of Lines in 3D (Cartesian & Vector form)
Maths Higher · Grade 12 · Week 32 · 25 questions
All 25 questions in this Equations of Lines in 3D (Cartesian & Vector form) quiz
Grade 12 Maths Higher — Equations of Lines in 3D (Cartesian & Vector form): 25 practice questions with instant scoring and explanations.
- Vector form of line passing through a with direction b: r =
- Parametric form of line r = a + tb gives:
- Cartesian form of line through (x₁, y₁, z₁) with direction ratios (a, b, c):
- Line through (1, 2, 3) with direction (1, -1, 2) has Cartesian form:
- Line passing through points A(1, 2, 3) and B(4, 5, 6):
- Condition for two lines r = a₁ + t·b₁ and r = a₂ + s·b₂ to be parallel:
- Condition for two lines to be perpendicular:
- Two skew lines are:
- Distance between point P and line r = a + tb is:
- Distance between two parallel lines r = a₁ + t·b and r = a₂ + t·b:
- Distance between two skew lines requires:
- Shortest distance between skew lines: d = |[(a₂-a₁)·(b₁ × b₂)]|/|b₁ × b₂|
- A line perpendicular to plane x + 2y - z = 0 has direction ratios:
- Foot of perpendicular from P to line r = a + tb is found by:
- Line r = (2,3,4) + t(1,2,3) passes through point:
- Angle θ between lines with direction vectors b₁ and b₂ is:
- Two lines are coplanar if scalar triple product [(a₂-a₁)·(b₁ × b₂)] =
- Symmetric form (x-1)/2 = (y+3)/(-1) = (z-2)/3 represents:
- If line (x-a)/l = (y-b)/m = (z-c)/n = k, then point on line is:
- Equations of coordinate axes:
- A line in the xy-plane satisfies:
- Lines (x-1)/1 = (y-2)/2 = (z-3)/3 and (x-4)/1 = (y-5)/2 = (z-6)/3 are:
- Point of intersection (if exists) of two lines found by:
- For line r = (1,2,3) + t(1,1,1), when does it pass through (2,3,4)?
- Review question for Equations of Lines in 3D (Cartesian & Vector form)
Question 1 of 250 correct so far