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Special Series – Σn, Σn², Σn³, Method of Differences

Maths Higher · Grade 11 · Week 23 · 25 questions

All 25 questions in this Special Series – Σn, Σn², Σn³, Method of Differences quiz

Grade 11 Maths HigherSpecial Series – Σn, Σn², Σn³, Method of Differences: 25 practice questions with instant scoring and explanations.

  1. ∑(r=1 to n) r =
  2. ∑(r=1 to n) r² =
  3. ∑(r=1 to n) r³ =
  4. The sum 1 + 2 + 3 + ... + 100 equals:
  5. ∑(r=1 to 10) r² =
  6. ∑(r=1 to 5) r³ =
  7. The sum 1² + 2² + 3² + ... + 20² equals:
  8. ∑(r=1 to n) (2r - 1) =
  9. The method of differences is used when:
  10. For the series 1·2 + 2·3 + 3·4 + ... + n(n+1), the sum is:
  11. ∑(r=1 to n) r(r+1) =
  12. The sum ∑(r=1 to 8) r³ equals:
  13. For the series 1/(1·2) + 1/(2·3) + 1/(3·4) + ... + 1/(n(n+1)), the sum is:
  14. ∑(r=1 to n) (r² - r) =
  15. The sum 1³ + 2³ + 3³ + ... + 10³ =
  16. ∑(r=1 to n) (2r² - r) =
  17. For the series 1·2·3 + 2·3·4 + ... + n(n+1)(n+2), the sum is:
  18. ∑(r=1 to 6) r(r + 1) =
  19. The sum of ∑(r=1 to n) 1/(r(r+1)(r+2)) is:
  20. ∑(r=1 to n) (r³ - r) =
  21. For finding ∑(r=1 to n) rⁿ using method of differences, we use:
  22. The sum ∑(r=1 to n) r/(r+1)! =
  23. ∑(r=1 to 12) r equals:
  24. The sum ∑(r=1 to n) 1/(r² + r) using partial fractions is:
  25. ∑(r=1 to n) r(r-1) =
Question 1 of 250 correct so far

∑(r=1 to n) r =